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시험 번호/코드: 70-457
시험 이름: Microsoft (Transition Your MCTS on SQL Server 2008 to MCSA: SQL Server 2012, Part 1)
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Q&A: 172 문항
업데이트: 2014-01-26
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인재도 많고 경쟁도 치열한 이 사회에서 IT업계 인재들은 인기가 아주 많습니다.하지만 팽팽한 경쟁률도 무시할 수 없습니다.많은 IT인재들도 어려운 인증시험을 패스하여 자기만의 자리를 지켜야만 합니다.우리 ITExamDump에서는 마침 전문적으로 이러한 IT인사들에게 편리하게 시험을 패스할수 있도록 유용한 자료들을 제공하고 있습니다. Microsoft 인증70-457인증은 아주 중요한 인증시험중의 하나입니다. ITExamDump의Microsoft 인증70-457로 시험을 한방에 정복하세요.
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NO.1 You are developing a database application by using Microsoft SQL Server 2012. You have a query that
runs slower than expected. You need to capture execution plans that will include detailed information on
missing indexes recommended by the query optimizer.
What should you do?
A. Add a HASH hint to the query.
B. Add a LOOP hint to the query.
C. Add a FORCESEEK hint to the query.
D. Add an INCLUDE clause to the index.
E. Add a FORCESCAN hint to the Attach query.
F. Add a columnstore index to cover the query.
G. Enable the optimize for ad hoc workloads option.
H. Cover the unique clustered index with a columnstore index.
I. Include a SET FORCEPLAN ON statement before you run the query.
J. Include a SET STATISTICS PROFILE ON statement before you run the query.
K. Include a SET STATISTICS SHOWPLAN_XML ON statement before you run the query.
L. Include a SET TRANSACTION ISOLATION LEVEL REPEATABLE READ statement before you run the
query.
M. Include a SET TRANSACTION ISOLATION LEVEL SNAPSHOT statement before you run the query.
N. Include a SET TRANSACTION ISOLATION LEVEL SERIALIZABLE statement before you run the
query.
Answer: K
Microsoft 70-457 70-457자료 70-457
NO.2 You are developing a database application by using Microsoft SQL Server 2012. An application that
uses a database begins to run slowly. Your investigation shows the root cause is a query against a
read-only table that has a clustered index.
The query returns the following six columns:
. One column in its WHERE clause contained in a non-clustered index
. Four additional columns
. One COUNT (*) column based on a grouping of the four additional columns
You need to optimize the statement. What should you do?
A. Add a HASH hint to the query.
B. Add a LOOP hint to the query.
C. Add a FORCESEEK hint to the query.
D. Add an INCLUDE clause to the index.
E. Add a FORCESCAN hint to the Attach query.
F. Add a columnstore index to cover the query.
G. Enable the optimize for ad hoc workloads option.
H. Cover the unique clustered index with a columnstore index.
I. Include a SET FORCEPLAN ON statement before you run the query.
J. Include a SET STATISTICS PROFILE ON statement before you run the query.
K. Include a SET STATISTICS SHOWPLAN_XML ON statement before you run the query.
L. Include a SET TRANSACTION ISOLATION LEVEL REPEATABLE READ statement before you run the
query.
M. Include a SET TRANSACTION ISOLATION LEVEL SNAPSHOT statement before you run the query.
N. Include a SET TRANSACTION ISOLATION LEVEL SERIALIZABLE statement before you run the
query.
Answer: F
Microsoft pdf 70-457시험문제 70-457 70-457최신덤프 70-457 pdf
NO.3 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure
that the following requirements are met:
. Students must be ranked based on their average marks.
. If one or more students have the same average, incremental ranks must be given based on the order
they are created.
. Ranks must be sequential without gaps in between.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code, RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code, DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks GROUP BY StudentCode
D. SELECT StudentCode as Code, NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM ( SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: C
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NO.4 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
. Students must be ranked based on their average marks.
. If one or more students have the same average, the same rank must be given to these students.
. Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use.?
A. SELECT StudentCode as Code, RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code, DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks GROUP BY StudentCode
D. SELECT StudentCode as Code, NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM ( SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: A
Microsoft 70-457 dump 70-457 dumps 70-457시험문제
NO.5 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure
that the top half of the students arranged by their average marks must be given a rank of 1 and the
remaining students must be given a rank of 2.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code,
DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value
FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: D
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